cos(2x)+(2sin^2x)-sin(x)=0

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Solution for cos(2x)+(2sin^2x)-sin(x)=0 equation: 


Simplifying
cos(2x) + (2sin2x) + -1sin(x) = 0

Remove parenthesis around (2x)
cos * 2x + (2sin2x) + -1sin(x) = 0

Reorder the terms for easier multiplication:
2cos * x + (2sin2x) + -1sin(x) = 0

Multiply cos * x
2cosx + (2sin2x) + -1sin(x) = 0

Multiply ins * x
2cosx + (2in2sx) + -1insx = 0

Reorder the terms:
2cosx + -1insx + (2in2sx) = 0

Solving
2cosx + -1insx + (2in2sx) = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add 'insx' to each side of the equation.
2cosx + -1insx + insx + (2in2sx) = 0 + insx

Combine like terms: -1insx + insx = 0
2cosx + 0 + (2in2sx) = 0 + insx
2cosx + (2in2sx) = 0 + insx
Remove the zero:
2cosx + (2in2sx) = insx

Add '(-2in2sx)' to each side of the equation.
2cosx + (2in2sx) + (-2in2sx) = insx + (-2in2sx)

Combine like terms: (2in2sx) + (-2in2sx) = 0
2cosx + 0 = insx + (-2in2sx)
2cosx = insx + (-2in2sx)

Divide each side by '2osx'.
c = 0.5ino-1 + (-1in2o-1)

Simplifying
c = 0.5ino-1 + (-1in2o-1)

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